Thread: surds

hello everyone!

18 divided by the square root of 3 has to be put into the form p times the square root of 3 where p is an integer

I get 18 sq root 2 by multiplying top and bottom by square root 3

the answers says 6 square root 3

I dont get it?!

Thank you

18/sqrt(3) = (6*3)/sqrt(3)

now as you probably know sqrt(3)*sqrt(3) = 3, thus we get:

<=> (6*3)/sqrt(3) = 6*(3/sqrt(3)) = 6*sqrt(3) ---> p = 6

ok so i get it like this

18/sq.rt.3 = 6 * 3/ sq.rt. 3 = (6 *(sq.rt.3 * sq.rt.3)) / sq.rt 3

the sq.rt.3 from the bottom cancels one from the top to leave

6*sq.rt.3

Right?

Right