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Math Help - surds

  1. #1
    Junior Member
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    surds

    hello everyone!

    18 divided by the square root of 3 has to be put into the form p times the square root of 3 where p is an integer

    I get 18 sq root 2 by multiplying top and bottom by square root 3

    the answers says 6 square root 3

    I dont get it?!

    Thank you
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  2. #2
    Senior Member Peritus's Avatar
    Joined
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    18/sqrt(3) = (6*3)/sqrt(3)

    now as you probably know sqrt(3)*sqrt(3) = 3, thus we get:

    <=> (6*3)/sqrt(3) = 6*(3/sqrt(3)) = 6*sqrt(3) ---> p = 6
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  3. #3
    Junior Member
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    ok so i get it like this

    18/sq.rt.3 = 6 * 3/ sq.rt. 3 = (6 *(sq.rt.3 * sq.rt.3)) / sq.rt 3

    the sq.rt.3 from the bottom cancels one from the top to leave

    6*sq.rt.3

    Right?
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  4. #4
    Senior Member Peritus's Avatar
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    Right
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