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Math Help - help with just one more problem

  1. #1
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    help with just one more problem

    ok i need help with just one more problem

    translate to an equation then solve

    the sum of five subtracted from eight times x is the same as thirteen plus the producted of two and the difference of x and two
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  2. #2
    Senior Member OReilly's Avatar
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    Quote Originally Posted by jim1174
    ok i need help with just one more problem

    translate to an equation then solve

    the sum of five subtracted from eight times x is the same as thirteen plus the producted of two and the difference of x and two
    8x-5=13+2(x-2)
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  3. #3
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    Quote Originally Posted by jim1174
    ok i need help with just one more problem
    translate to an equation then solve
    the sum of five subtracted from eight times x is the same as thirteen plus the producted of two and the difference of x and two
    Hello,

    as OReilly has posted the equation is
    8x-5=13+2(x-2)
    Expand the RHS :
    8x-5= 13 + 2x - 4
    8x - 5 = 2x +9
    Take the variable to the LHS, the constants to the RHS:
    6x = 14
    Divide both sides by 6:
    x=\frac{14}{6}=\frac{7}{3}

    To proof, plug the value into the origianl equation:
    8 \cdot \frac{7}{3}-5=13+2(\frac{7}{3}-2)
     \frac{56}{3}-5=13+2(\frac{1}{3})
     \frac{56-15}{3}=13+\frac{2}{3}
     \frac{41}{3}=\frac{39+2}{3}

    So the solution is OK

    Greetings

    EB
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