# Thread: help with just one more problem

1. ## help with just one more problem

ok i need help with just one more problem

translate to an equation then solve

the sum of five subtracted from eight times x is the same as thirteen plus the producted of two and the difference of x and two

2. Originally Posted by jim1174
ok i need help with just one more problem

translate to an equation then solve

the sum of five subtracted from eight times x is the same as thirteen plus the producted of two and the difference of x and two
8x-5=13+2(x-2)

3. Originally Posted by jim1174
ok i need help with just one more problem
translate to an equation then solve
the sum of five subtracted from eight times x is the same as thirteen plus the producted of two and the difference of x and two
Hello,

as OReilly has posted the equation is
8x-5=13+2(x-2)
Expand the RHS :
8x-5= 13 + 2x - 4
8x - 5 = 2x +9
Take the variable to the LHS, the constants to the RHS:
6x = 14
Divide both sides by 6:
$x=\frac{14}{6}=\frac{7}{3}$

To proof, plug the value into the origianl equation:
$8 \cdot \frac{7}{3}-5=13+2(\frac{7}{3}-2)$
$\frac{56}{3}-5=13+2(\frac{1}{3})$
$\frac{56-15}{3}=13+\frac{2}{3}$
$\frac{41}{3}=\frac{39+2}{3}$

So the solution is OK

Greetings

EB