ok i need help with just one more problem

translate to an equation then solve

the sum of five subtracted from eight times x is the same as thirteen plus the producted of two and the difference of x and two

Results 1 to 3 of 3

- Apr 16th 2006, 10:47 PM #1

- Joined
- Mar 2006
- Posts
- 14

- Apr 17th 2006, 01:40 AM #2

- Apr 17th 2006, 07:23 AM #3Originally Posted by
**jim1174**

as OReilly has posted the equation is

8x-5=13+2(x-2)

Expand the RHS :

8x-5= 13 + 2x - 4

8x - 5 = 2x +9

Take the variable to the LHS, the constants to the RHS:

6x = 14

Divide both sides by 6:

$\displaystyle x=\frac{14}{6}=\frac{7}{3}$

To proof, plug the value into the origianl equation:

$\displaystyle 8 \cdot \frac{7}{3}-5=13+2(\frac{7}{3}-2)$

$\displaystyle \frac{56}{3}-5=13+2(\frac{1}{3})$

$\displaystyle \frac{56-15}{3}=13+\frac{2}{3}$

$\displaystyle \frac{41}{3}=\frac{39+2}{3}$

So the solution is OK

Greetings

EB