help

Quote:

Originally Posted by jim1174

can some one show me how to do this problem

negative four times the sum of n and seven is equal to negative five times n minus nine

Translated into an equation this is:

$ (-4)(n+7)=(-5)(n-9) $

Multiply both sides of the equation by $-1/4$ , and as
a "-" times a "-" is a "+" this gives:

$ n+7=(5/4)(n-9) $

Now expand the brackets on the Right Hand Side of the equation:

$ n+7=\frac{5}{4}n-\frac{45}{4} $

Add 45/4 to both sides of the equation:

$ n+\frac{73}{4}=\frac{5}{4}n $ .

Subtract $n$ from both sides:

$ \frac{73}{4}=\frac{1}{4}n $ .

Finlay multiply both sides by 4:

$ 73=n $ ,

so $n=73$

RonL