Results 1 to 5 of 5

Math Help - Simple for you.. hard for me :(

  1. #1
    Newbie
    Joined
    Jan 2008
    Posts
    3

    Simple for you.. hard for me :(

    [2 - y-6q/y-3q] / [y2 -16q2/y2 - 2yq - 5q2] / y2 + yq - 12q2 / 4y + 8yq

    Any help is greatly appreciated
    Last edited by anakinmalta; January 3rd 2008 at 08:12 AM. Reason: Mistake
    Follow Math Help Forum on Facebook and Google+

  2. #2
    GAMMA Mathematics
    colby2152's Avatar
    Joined
    Nov 2007
    From
    Alexandria, VA
    Posts
    1,172
    Awards
    1
    Quote Originally Posted by anakinmalta View Post
    [2 - y-6q/y-3q] / [y2 -16q2/y2 - 2yq - 5q2] / y2 + yq - 12q2 / 4y + 8yq

    Any help is greatly appreciated
    Order of operations says to attack the brackets first, then the parenthesis, then multiplication, division, addition, and subtraction last. Are you sure there are no brackets or parenthesis around your third and fourth group of terms?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Jan 2008
    Posts
    3
    the last part is 1 part so there is no 4th part... and yes there is no brackets.

    I know how to tackle them... I can't get it working
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    10,212
    Thanks
    419
    Awards
    1
    Quote Originally Posted by anakinmalta View Post
    the last part is 1 part so there is no 4th part... and yes there is no brackets.

    I know how to tackle them... I can't get it working
    Once again I'm going to be anal, but this time in a good cause, at least.

    You are saying that your problem is to simplify
    \frac{\left ( \frac{2 - y - \frac{6q}{y} - 3q}{y^2 - \frac{16q^2}{y^2} - 2yq - 5q^2} \right )}{y^2} + yq - \frac{12q^2}{4y} + 8yq

    Since I really doubt this is what you are trying to work with, please use parentheses to clear this up. There are too many ways to interpret this otherwise.

    -Dan
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Newbie
    Joined
    Jan 2008
    Posts
    3
    Thanks, though I managed to work it out after a lot of trial and error
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Really simple question too hard for a simple mind
    Posted in the Statistics Forum
    Replies: 2
    Last Post: October 5th 2010, 09:03 AM
  2. Probability Question- could be simple/could be hard??
    Posted in the Advanced Statistics Forum
    Replies: 1
    Last Post: May 7th 2010, 05:56 AM
  3. simple yet hard finding area + volume question
    Posted in the Calculus Forum
    Replies: 0
    Last Post: September 25th 2009, 08:27 PM
  4. Simple, yet hard...
    Posted in the Discrete Math Forum
    Replies: 11
    Last Post: March 28th 2009, 01:27 PM
  5. simple questions hard to get the answer
    Posted in the Statistics Forum
    Replies: 3
    Last Post: May 27th 2005, 04:12 PM

Search Tags


/mathhelpforum @mathhelpforum