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Math Help - algebra help

  1. #1
    becs101
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    algebra help

    hi there. i was wondering if any one could explain to me how to put this equation:

    2^n * 8^n /2^2n * 16 in the form of 2^(an+b) the book says the answer is 2^(2n-a) i just cant work out hoe to solve it.

    another equation i need help with is:
    write 2^-x * 3^-x * 6^2x * 3^2x * 2^2x as a power of 6, the book says the answer is 6^3x but again i cant work out how to get that.

    it would be great if someone could give me a hand and show me how to solve these types of equations. thnx heapz.
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  2. #2
    Eater of Worlds
    galactus's Avatar
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    \frac{2^{n}8^{n}}{2^{2n}2^{4}}

    The numerator: 2^{n}8^{n}=16^{n}

    The denominator: 2^{2n}16= 16\cdot{4^{n}}

    This gives us \frac{4^{n}}{16}=2^{2n}2^{-4}=\boxed{2^{2n-4}}
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