algebra help

becs101 · January 1st 2008, 05:02 PM

hi there. i was wondering if any one could explain to me how to put this equation:

2^n * 8^n /2^2n * 16 in the form of 2^(an+b) the book says the answer is 2^(2n-a) i just cant work out hoe to solve it.

another equation i need help with is:
write 2^-x * 3^-x * 6^2x * 3^2x * 2^2x as a power of 6, the book says the answer is 6^3x but again i cant work out how to get that.

it would be great if someone could give me a hand and show me how to solve these types of equations.

thnx heapz.

**galactus** · January 1st 2008, 05:23 PM

$\frac{2^{n}8^{n}}{2^{2n}2^{4}}$

The numerator: $2^{n}8^{n}=16^{n}$

The denominator: $2^{2n}16= 16\cdot{4^{n}}$

This gives us $\frac{4^{n}}{16}=2^{2n}2^{-4}=\boxed{2^{2n-4}}$

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