Given that the roots of the equation x^2 + ax + (a + 2) = 0 differ by 2, find the possible values of the constant a. ans= -2 and 6 Can anyone show me how to work out this question please? cheers
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so the roots are so your factorised expression is so expand giving compare terms of same order giving and so all you need to do is solve this system to find the two values of a. Note an alternative method is to use the quad formula.
Originally Posted by sparky69er Given that the roots of the equation x^2 + ax + (a + 2) = 0 differ by 2, find the possible values of the constant a. ans= -2 and 6 Can anyone show me how to work out this question please? cheers A slightly different way. We know that and by the quadratic formula, where r1 and r2 are the solutions to the quadratic. Thus Solve for a. -Dan
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