Hello, how would i go about dividing 6+$\displaystyle \sqrt40$ divided by 2?. The answer in the book is 3+$\displaystyle \sqrt10$ but i don't see how to get that. Can somebody please help?
Hello, how would i go about dividing 6+$\displaystyle \sqrt40$ divided by 2?. The answer in the book is 3+$\displaystyle \sqrt10$ but i don't see how to get that. Can somebody please help?