A father is nine times the age of his son. In 5 years, he will be four times the age of his son. How old are they now?

Omg, after finishing the qudratics chapter, ive forgotten some algebra. Please help me out.

Thanks in advance

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- Apr 10th 2006, 06:04 AM #1

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- Apr 10th 2006, 06:09 AM #2

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Let the son's age = X

Then Father's Age = 9X

In 5 years

Son's age = X+5

Father's age = 9X+5

But it is given that the father will be 4 times as old

i.e. 9X+5 = 4(X+5)

9X+5 = 4X+20

5X = 15

X = 3

So the son's age is 3 years

And the father's age = 9x3 = 27years

p.s. On a completely different note, the father had his son when he was 24.

I am 24!!!!