Determine the equation of the parabola that opens downward from (1,-3) and is congruent to y=2(x-4)2.
Do you mean this: y=2(x-4)^2
or this: y=2(x-4)+2
or something else?
I'll GUESS that it's this: y=2(x-4)^2
This suggests a parabola oppening up and vertex at (4,0).
A "congruent" parabola, then, with the other requirements, might be y=-2(x-1)^2 - 3
Really, it goes straight to the heart of understanding the form of the equation. There isn't anything magic or calculation-intensive about it.