can anyone simplify this:

(a2b3c)(a3b-4c2d)

also:

LogV=(w) log T

pz

make w the subject when:

V=25

P=1.34

Z=37.62

T=20

the answer i had was 54.165 is this correct?

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- Dec 21st 2007, 08:38 AM #1

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- Dec 21st 2007, 08:59 AM #2

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Hello, jenko!

Simplify: .$\displaystyle (a^2b^3c)(a^3b - 4c^2d)$

$\displaystyle \log(V) \:=\:\frac{w}{pz}\log(T)$

Make $\displaystyle w$ the subject when: .$\displaystyle V=25,\;p=1.34,\;Z=37.62,\;T=20$

The answer i had was 54.165 . . . Is this correct? . . . . Yes!

We have: .$\displaystyle \frac{w}{pz}\log(T) \:=\:\log(V)\quad\Rightarrow\quad w \:=\:\frac{pz\log(V)}{\log(T)} $

Then: .$\displaystyle w \;=\;\frac{(1.34)(37.62)\log(25)}{\log(20)} \;=\;54.16575669$

. .*Good work!*

- Dec 21st 2007, 09:13 AM #3

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- Dec 21st 2007, 09:30 AM #4