# Math Help - help!

1. ## help!

can anyone simplify this:

(a2b3c)(a3b-4c2d)
also:
LogV=(w) log T
pz

make w the subject when:
V=25
P=1.34
Z=37.62
T=20

the answer i had was 54.165 is this correct?

2. Hello, jenko!

Simplify: . $(a^2b^3c)(a^3b - 4c^2d)$
Well, we can multiply it out: . $a^5b^4c - 4a^2b^3c^3d$

$\log(V) \:=\:\frac{w}{pz}\log(T)$

Make $w$ the subject when: . $V=25,\;p=1.34,\;Z=37.62,\;T=20$

The answer i had was 54.165 . . . Is this correct? . . . . Yes!
I would solve for $w$ first . . .

We have: . $\frac{w}{pz}\log(T) \:=\:\log(V)\quad\Rightarrow\quad w \:=\:\frac{pz\log(V)}{\log(T)}$

Then: . $w \;=\;\frac{(1.34)(37.62)\log(25)}{\log(20)} \;=\;54.16575669$

. . Good work!

3. (a2b3c)(a3b-4c2d)

this is the right equation sorry!

4. Originally Posted by jenko
(a2b3c)(a3b-4c2d)

this is the right equation sorry!
Soroban already answered this, but if those #'s aren't exponents and are indeed coefficients, then your answer is:

$(a2b3c)(a3b-4c2d) = 18a^2b^2c - 48a^2bc^2d$