Is there an easy way to solve nonlinear equations such as
2^(x^3-4x) = (x - 1)
besides graphing?
Also how would you go about solving 16^(x+2) = 8^x
Hello, BarlowBarlow1!
Well, the answer can be approximated by any of several available methods.Is there an easy way to solve nonlinear equations such as
$\displaystyle 2^{x^3-4x} \:= \: x - 1$ .besides graphing?
Solve: .$\displaystyle 16^{x+2} \:= \:8^x$
We have: .$\displaystyle (2^4)^{x+2} \:=\:(2^3)^x\quad\Rightarrow\quad2^{4x+8} \:=\:2^{3x}$
Therefore: .$\displaystyle 4x + 8 \:=\:3x\quad\Rightarrow\quad x \:=\:-8$