arrange 2^75, 3^50, 7^25

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- Dec 18th 2007, 11:57 PMafeasfaerw23231233arrange 2^75, 3^50, 7^25
arrange 2^75, 3^50, 7^25

- Dec 19th 2007, 02:07 AMJaneBennet
Compare $\displaystyle 2^3$, $\displaystyle 3^2$ and 7 (put them in order of size), then raise to the power of 25.

For example, $\displaystyle 2^3=8$ and $\displaystyle 3^2=9$, so $\displaystyle 2^3<3^2$; therefore

$\displaystyle 2^{75}\ =\ (2^3)^{25}\ <\ (3^2)^{25}\ =\ 3^{50}$

Do the same with the 7 as well.