1. [SOLVED] factoring

Curious:

I am correct in assuming that

p^2q^2 - 5pq - 18

is not a perfect square and therefore cannot be factored??

2. Originally Posted by VB89
Curious:

I am correct in assuming that

p^2q^2 - 5pq - 18

is not a perfect square and therefore cannot be factored??
Put $u=\frac{5+\sqrt{97}}{2}$ and $v=\frac{5-\sqrt{97}}{2}$ then:

$p^2q^2 - 5pq - 18 =(pq -u)(pq-v)$

RonL