Curious: I am correct in assuming that p^2q^2 - 5pq - 18 is not a perfect square and therefore cannot be factored??
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Originally Posted by VB89 Curious: I am correct in assuming that p^2q^2 - 5pq - 18 is not a perfect square and therefore cannot be factored?? Put $\displaystyle u=\frac{5+\sqrt{97}}{2}$ and $\displaystyle v=\frac{5-\sqrt{97}}{2}$ then: $\displaystyle p^2q^2 - 5pq - 18 =(pq -u)(pq-v)$ RonL
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