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Math Help - [SOLVED] factoring

  1. #1
    VB89
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    [SOLVED] factoring

    Curious:

    I am correct in assuming that

    p^2q^2 - 5pq - 18

    is not a perfect square and therefore cannot be factored??
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by VB89 View Post
    Curious:

    I am correct in assuming that

    p^2q^2 - 5pq - 18

    is not a perfect square and therefore cannot be factored??
    Put u=\frac{5+\sqrt{97}}{2} and v=\frac{5-\sqrt{97}}{2} then:

    p^2q^2 - 5pq - 18 =(pq -u)(pq-v)

    RonL
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