Trying to remember...

**Morzilla** · December 16th 2007, 08:12 AM

In using radicals, square roots, and powers;

when trying to figure the square root of a number with a radical such as;

$(64x^8)^\frac{1}{2}$

Now in figuring out the $x^8$ from the square root I know that 64 is 8, but the $x^8$ is $x^4$ does this mean that in order to get 4 we subtract 4 from 8? Meaning that for figuring out the square root of 64 is basically division(multiplication) but on the radicals, is it subtraction(addition)!?

Hope I made sense...!!

Thanks

**Morzilla** · December 16th 2007, 08:16 AM

yeah I just paged over mu notes and I found the answer to my own question...Sorry for the inconvenience!!!!

**Jhevon** · December 16th 2007, 09:51 AM

Originally Posted by Morzilla

yeah I just paged over mu notes and I found the answer to my own question...Sorry for the inconvenience!!!!

that's good. you should learn the laws of exponents very well. you may also find this helpful. see post number 3

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Trying to remember...

No no I got it.....Sorry!!

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