Trying to remember...

• Dec 16th 2007, 09:12 AM
Morzilla
Trying to remember...
In using radicals, square roots, and powers;

when trying to figure the square root of a number with a radical such as;

$(64x^8)^\frac{1}{2}$

Now in figuring out the $x^8$ from the square root I know that 64 is 8, but the $x^8$ is $x^4$ does this mean that in order to get 4 we subtract 4 from 8? Meaning that for figuring out the square root of 64 is basically division(multiplication) but on the radicals, is it subtraction(addition)!?

Hope I made sense...!!

Thanks
• Dec 16th 2007, 09:16 AM
Morzilla
No no I got it.....Sorry!!
yeah I just paged over mu notes and I found the answer to my own question...Sorry for the inconvenience!!!! :(
• Dec 16th 2007, 10:51 AM
Jhevon
Quote:

Originally Posted by Morzilla
yeah I just paged over mu notes and I found the answer to my own question...Sorry for the inconvenience!!!! :(

that's good. you should learn the laws of exponents very well. you may also find this helpful. see post number 3