Firstmy math question....

I am asked to solve this

$\displaystyle 2x+5y=-2$

$\displaystyle 15y=-6-6x$

I followed these examples Systems of Equations - Solve by addition or subtraction and thus this occurred...

$\displaystyle 6(2x+5y=-2)$

$\displaystyle 2(6x+15y=-6)$

$\displaystyle 12x+10y=12$

$\displaystyle (-1)(12x+30y=-12)$

$\displaystyle 12x+10y=-12$

$\displaystyle -12x-30y=12$

$\displaystyle 20y=0$

$\displaystyle \frac{20y}{20}=\frac{0}{20}$

cancel the $\displaystyle 20$s and I'm left with

$\displaystyle y=0$

Now to solve for $\displaystyle x$

I plug in $\displaystyle y=o$ into the second equation $\displaystyle 6x+15y=-6$

$\displaystyle 6x+15(0)=-6$

$\displaystyle 6x=-6$

$\displaystyle \frac{6x}{6}=\frac{-6}{6}$

cancel...

and $\displaystyle x=-1$

Ok now that I have the $\displaystyle x$s and the $\displaystyle y$s I plug those into the first equation....right so far?!

$\displaystyle 2(-1)+5(0)=-2$

$\displaystyle -2=-2$

Did I do this right?! if not, then where did I go wrong, I have a hard time with these types of equations because I can never figure out elimination/addition nor graphing!!

NOW FOR MY SECOND QUESTIONwhat has happened to theMessage:options that used to be above the text box!?

Many thanks!!!