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Math Help - Please show me how to solve this equation

  1. #1
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    Please show me how to solve this equation

    500/1+25e^.3x=200
    please show me the steps you would take to solve this equation.
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by bilbobaggins View Post
    500/1+25e^.3x=200
    please show me the steps you would take to solve this equation.
    I presume this is
    \frac{500}{1 + 25e^{0.3x}} = 200

    PLEASE use parenthesis!

    500 = 200(1 + 25e^{0.3x})

    1 + 25e^{0.3x} = \frac{500}{200} = \frac{5}{2}

    25e^{0.3x} = \frac{5}{2} - 1 = \frac{3}{2}

    Can you finish from here?

    -Dan
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  3. #3
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    Quote Originally Posted by topsquark View Post
    I presume this is
    \frac{500}{1 + 25e^{0.3x}} = 200

    PLEASE use parenthesis!

    500 = 200(1 + 25e^{0.3x})

    1 + 25e^{0.3x} = \frac{500}{200} = \frac{5}{2}

    25e^{0.3x} = \frac{5}{2} - 1 = \frac{3}{2}

    Can you finish from here?

    -Dan




    25e^3= 3.55^x = 3/2?
    And then from that point is there anyway to solve algebraically or is it calc only? Or do we use natural logs?
    Last edited by bilbobaggins; December 14th 2007 at 07:15 PM.
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  4. #4
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by bilbobaggins View Post
    25e^3= 3.55^x = 3/2?
    And then from that point is there anyway to solve algebraically or is it calc only? Or do we use natural logs?
    You are trying to be too complicated with this. Divide both sides by 25 to get the exponential term alone and then take the natural log of both sides. Then solve for x.

    -Dan
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