can someone tell me if i am doing this right? Convert the following equations into logarithmic form: y=bx logb(y)=x a. 9 = 4x 9=4^x log4(9)=x b. 3 = 6y 3=6^y log6(3)=y c. 5 = 7y 5=7^y log7(5)=y d. X = 9y x=9^y log9(x)=y
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Originally Posted by brandilee can someone tell me if i am doing this right? Convert the following equations into logarithmic form: y=bx logb(y)=x a. 9 = 4x 9=4^x log4(9)=x b. 3 = 6y 3=6^y log6(3)=y c. 5 = 7y 5=7^y log7(5)=y d. X = 9y x=9^y log9(x)=y Whaaaat? If y = bx then If y = b^x then . Is this what you are trying to say? (This is correct.) Then what's this "9 = 4x" thing in front of the " ?" -Dan
(I assume that you accidentally wrote those 9 = 4x, 3 = 6y, 5 = 7y..) , , , ,
yeah, thats what i meant. i dont know how to make the numbers above or below. thanks
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