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Math Help - equations to log form, is this correct?

  1. #1
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    equations to log form, is this correct?

    can someone tell me if i am doing this right?

    Convert the following equations into logarithmic form: y=bx logb(y)=x

    a. 9 = 4x 9=4^x log4(9)=x

    b. 3 = 6y 3=6^y log6(3)=y

    c. 5 = 7y 5=7^y log7(5)=y

    d. X = 9y x=9^y log9(x)=y
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by brandilee View Post
    can someone tell me if i am doing this right?

    Convert the following equations into logarithmic form: y=bx logb(y)=x

    a. 9 = 4x 9=4^x log4(9)=x

    b. 3 = 6y 3=6^y log6(3)=y

    c. 5 = 7y 5=7^y log7(5)=y

    d. X = 9y x=9^y log9(x)=y
    Whaaaat?
    If y = bx then x \neq log_b(y)

    If y = b^x then x = log_b(y). Is this what you are trying to say? (This is correct.)

    Then what's this "9 = 4x" thing in front of the " 9 = 4^x?"

    -Dan
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  3. #3
    Super Member wingless's Avatar
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    (I assume that you accidentally wrote those 9 = 4x, 3 = 6y, 5 = 7y..)

    4^x = 9,
    x = \text{log}_49

    6^y = 3,
    y = \text{log}_63

    7^y = 5,
    y = \text{log}_75

    9^y = x,
    y = \text{log}_9x
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  4. #4
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    yeah, thats what i meant. i dont know how to make the numbers above or below. thanks
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