can someone tell me if i am doing this right?
Convert the following equations into logarithmic form: y=bx logb(y)=x
a. 9 = 4x 9=4^x log4(9)=x
b. 3 = 6y 3=6^y log6(3)=y
c. 5 = 7y 5=7^y log7(5)=y
d. X = 9y x=9^y log9(x)=y
can someone tell me if i am doing this right?
Convert the following equations into logarithmic form: y=bx logb(y)=x
a. 9 = 4x 9=4^x log4(9)=x
b. 3 = 6y 3=6^y log6(3)=y
c. 5 = 7y 5=7^y log7(5)=y
d. X = 9y x=9^y log9(x)=y
(I assume that you accidentally wrote those 9 = 4x, 3 = 6y, 5 = 7y..)
$\displaystyle 4^x = 9$,
$\displaystyle x = \text{log}_49$
$\displaystyle 6^y = 3$,
$\displaystyle y = \text{log}_63$
$\displaystyle 7^y = 5$,
$\displaystyle y = \text{log}_75$
$\displaystyle 9^y = x$,
$\displaystyle y = \text{log}_9x$