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Math Help - Help with algebra

  1. #1
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    Help with algebra

    Could someone please explain and tell me the answer to these questions i would really appreciate it thanxx

    Q1. Simplify 4xy(cubed)x 3x(squared)y

    Q2. Factorise p(squared)-16q(squared)


    Ps does anyone know how to get the squared and cubed sign on the keyboard?
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  2. #2
    MHF Contributor kalagota's Avatar
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    Quote Originally Posted by sammyfox07 View Post
    Could someone please explain and tell me the answer to these questions i would really appreciate it thanxx
    Quote Originally Posted by sammyfox07 View Post
    Q1. Simplify 4xy(cubed)x 3x(squared)y
    i cant understand..
    Quote Originally Posted by sammyfox07 View Post
    Q2. Factorise p(squared)-16q(squared)
    note that a^2 - b^2 = (a+b)(a-b)

    now, do it with your given.. your given is p^2 - 16q^2 = p^2 - (4q)^2

    Quote Originally Posted by sammyfox07 View Post
    Ps does anyone know how to get the squared and cubed sign on the keyboard?
    group accordingly.. use ^ for power.. or the best thing is, learn LaTex (it is easy)..
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  3. #3
    MHF Contributor
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    Squared and cubed

    There are many ways to do that. The easiest is just to use carefully the symbol "^".

    x-squared might be x^2
    y-cubed might be y^3

    But be careful. Use parentheses to clarify meaning. These are very different:

    a^(s+2) and a^s+2

    Alternatively, one could learn just a bit of LaTeX.

    Rule of thumb, if you use the variable 'x', don't even think of using 'x' to mean multiplication. That is VERY confusing. Dots, parentheses, or simply juxtaposition are quite sufficient.

    (4xy^3)(3(x^2)y)

    See how I added some parentheses just to make sure it was understood?

    Just collect exponents.

    (4xy^3)(3(x^2)y) = 4 * x * y^3 * 3 * x^2 * y

    This time, I used stars for multiplication and spaces to clarify intent.

    (4xy^3)(3(x^2)y) = 4 * x * y^3 * 3 * x^2 * y = 4*3 * x^(1+2) * y^(3+1)

    Again, parentheses are used to clarify intent. Do you know where the '1's came from? x = x^1, right?

    Finally,

    (4xy^3)(3(x^2)y) = 4*3 * x^(1+2) * y^(3+1) = 12(x^3)y^3 = 12(xy)^3
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