How can i simplify the following? help please

16 1/2
-------
81 3/4 do i need to add the fractions then divide or flip..

also

12(a^3b^2c)^4
-----------------
4a^2c^6

thank you

2. Originally Posted by Chez_
How can i simplify the following? help please

16 1/2
-------
81 3/4 do i need to add the fractions then divide or flip..

also

12(a^3b^2c)^4
-----------------
4a^2c^6

thank you
$\frac{ 16 + \frac{1}{2} }{ 81 + \frac{3}{4} }$

$= \frac{ \frac{33}{2} }{ \frac{327}{4} }$

$= \frac{33}{2} \times \frac{4}{327}$

$= \frac{33 \times 2}{327}$

$= \frac{66}{327}$

$= \frac{22}{109}$

------------

$\frac{ 12 ( a^{3} b^{2} c ) ^{4} }{ 4 ( a^{2} c^{6} ) }$

$= \frac{ 3( a^{12} b^8 c^4 ) }{ ( a^2c^6 ) }$

$= \frac{ 3 a^{10} b^2 }{ c^2 }$

3. Originally Posted by Chez_
How can i simplify the following? help please

16 1/2
-------
81 3/4 do i need to add the fractions then divide or flip..

also

12(a^3b^2c)^4
-----------------
4a^2c^6

thank you
16.5 = 33/2
81.75 = 327/4
$\frac{\frac{33}{2}}{\frac{327}{4}} = \frac{33}{2}\frac{4}{327}$
$=\frac{4*33}{2*327}$
$=\frac{2*11}{109}$
$=\frac{22}{109}$

4. Originally Posted by colby2152
16.5 = 33/2
81.75 = 327/4
$\frac{\frac{33}{2}}{\frac{327}{4}} = \frac{33}{2}\frac{4}{327}$
$=\frac{4*33}{2*327}$
$=\frac{2*11}{109}$
$=\frac{22}{109}$
Colby use \times for $\times$ and \div for $\div$

5. Originally Posted by janvdl
Colby use \times for $\times$ and \div for $\div$
I prefer \cdot for multiplication. Ever since I started Algebra I have hated any symbol that looks like an x but isn't the variable.

-Dan

6. Originally Posted by topsquark
I prefer \cdot for multiplication. Ever since I started Algebra I have hated any symbol that looks like an x but isn't the variable.

-Dan
I hate the x symbols for multiplication as well. An asterisk is fairly easy to type, and it's a cross between the x and dot, so I'll stick with it for now!