How can i simplify the following? help please

16 1/2

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81 3/4 do i need to add the fractions then divide or flip..

also

12(a^3b^2c)^4

-----------------

4a^2c^6

thank you

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- Dec 12th 2007, 03:04 AMChez_help please
How can i simplify the following? help please

16 1/2

-------

81 3/4 do i need to add the fractions then divide or flip..

also

12(a^3b^2c)^4

-----------------

4a^2c^6

thank you - Dec 12th 2007, 04:43 AMjanvdl
$\displaystyle \frac{ 16 + \frac{1}{2} }{ 81 + \frac{3}{4} }$

$\displaystyle = \frac{ \frac{33}{2} }{ \frac{327}{4} }$

$\displaystyle = \frac{33}{2} \times \frac{4}{327}$

$\displaystyle = \frac{33 \times 2}{327}$

$\displaystyle = \frac{66}{327}$

$\displaystyle = \frac{22}{109}$

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$\displaystyle \frac{ 12 ( a^{3} b^{2} c ) ^{4} }{ 4 ( a^{2} c^{6} ) }$

$\displaystyle = \frac{ 3( a^{12} b^8 c^4 ) }{ ( a^2c^6 ) }$

$\displaystyle = \frac{ 3 a^{10} b^2 }{ c^2 }$ - Dec 12th 2007, 04:44 AMcolby2152
- Dec 12th 2007, 04:51 AMjanvdl
- Dec 12th 2007, 08:24 AMtopsquark
- Dec 13th 2007, 05:18 AMcolby2152