# Thread: Divide using long division

1. ## Divide using long division

(x squared + 8x +3) / (x+2)

2. Originally Posted by lovely08
(x squared + 8x +3) / (x+2)
$\displaystyle x+6$
--------------------
$\displaystyle x^2 + 8x + 3$
$\displaystyle -x^2 - 2x$
______________
$\displaystyle 6x + 3$
$\displaystyle -6x - 12$
______________
$\displaystyle -9$

So $\displaystyle x^2 + 8x + 3 = (x + 2)(x + 6) - 9$

3. Originally Posted by lovely08
$\displaystyle x^2 + 8x + 3 \div \left| \!{\underline {\, {x + 2} \,}} \right.$
$\displaystyle \noindent\begin{array}{*{20}c}~~~\,x^2&+~~8x&+~~3& \div&\left|\!{\underline{\,{x+2}\,}}\right.&=&x\,+ \,6\,-\,\dfrac9{x+2}.\\ -~x^2&-~~2x&\\\cline{0-1} &~~~\,~6x&+~~3&\\ &-~\,\,6x&-\,12&\\\cline{2-3} &&-~~9 \end{array}$

Ufff... it's been a long time I used to type long division

4. Originally Posted by Krizalid
$\displaystyle \noindent\begin{array}{*{20}c}~~~\,x^2&+~~8x&+~~3& \div&\left|\!{\underline{\,{x+2}\,}}\right.&=&x\,+ \,6\,-\,\dfrac9{x+2}.\\ -~x^2&-~~2x&\\\cline{0-1} &~~~\,~6x&+~~3&\\ &-~\,\,6x&-\,12&\\\cline{2-3} &&-~~9 \end{array}$

Ufff... it's been a long time I used to type long division
Your's looks so much nicer than mine... Time I learnt some more LaTeX