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Math Help - Divide using long division

  1. #1
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    Divide using long division

    (x squared + 8x +3) / (x+2)
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  2. #2
    Bar0n janvdl's Avatar
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    Quote Originally Posted by lovely08 View Post
    (x squared + 8x +3) / (x+2)
    x+6
    --------------------
    x^2 + 8x + 3
    -x^2 - 2x
    ______________
    6x + 3
    -6x - 12
    ______________
    -9

    So x^2 + 8x + 3 = (x + 2)(x + 6) - 9
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  3. #3
    Math Engineering Student
    Krizalid's Avatar
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    Quote Originally Posted by lovely08 View Post
    x^2 + 8x + 3 \div \left| \!{\underline {\,<br />
{x + 2} \,}} \right.
    \noindent\begin{array}{*{20}c}~~~\,x^2&+~~8x&+~~3&  \div&\left|\!{\underline{\,{x+2}\,}}\right.&=&x\,+  \,6\,-\,\dfrac9{x+2}.\\<br />
-~x^2&-~~2x&\\\cline{0-1}<br />
&~~~\,~6x&+~~3&\\<br />
&-~\,\,6x&-\,12&\\\cline{2-3}<br />
&&-~~9<br />
\end{array}

    Ufff... it's been a long time I used to type long division
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  4. #4
    Bar0n janvdl's Avatar
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    Quote Originally Posted by Krizalid View Post
    \noindent\begin{array}{*{20}c}~~~\,x^2&+~~8x&+~~3&  \div&\left|\!{\underline{\,{x+2}\,}}\right.&=&x\,+  \,6\,-\,\dfrac9{x+2}.\\<br />
-~x^2&-~~2x&\\\cline{0-1}<br />
&~~~\,~6x&+~~3&\\<br />
&-~\,\,6x&-\,12&\\\cline{2-3}<br />
&&-~~9<br />
\end{array}

    Ufff... it's been a long time I used to type long division
    Your's looks so much nicer than mine... Time I learnt some more LaTeX
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