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Thread: Divide using long division

  1. #1
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    Divide using long division

    (x squared + 8x +3) / (x+2)
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  2. #2
    Bar0n janvdl's Avatar
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    Quote Originally Posted by lovely08 View Post
    (x squared + 8x +3) / (x+2)
    $\displaystyle x+6$
    --------------------
    $\displaystyle x^2 + 8x + 3$
    $\displaystyle -x^2 - 2x$
    ______________
    $\displaystyle 6x + 3$
    $\displaystyle -6x - 12$
    ______________
    $\displaystyle -9$

    So $\displaystyle x^2 + 8x + 3 = (x + 2)(x + 6) - 9$
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  3. #3
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    Krizalid's Avatar
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    Quote Originally Posted by lovely08 View Post
    $\displaystyle x^2 + 8x + 3 \div \left| \!{\underline {\,
    {x + 2} \,}} \right.$
    $\displaystyle \noindent\begin{array}{*{20}c}~~~\,x^2&+~~8x&+~~3& \div&\left|\!{\underline{\,{x+2}\,}}\right.&=&x\,+ \,6\,-\,\dfrac9{x+2}.\\
    -~x^2&-~~2x&\\\cline{0-1}
    &~~~\,~6x&+~~3&\\
    &-~\,\,6x&-\,12&\\\cline{2-3}
    &&-~~9
    \end{array}$

    Ufff... it's been a long time I used to type long division
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  4. #4
    Bar0n janvdl's Avatar
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    Quote Originally Posted by Krizalid View Post
    $\displaystyle \noindent\begin{array}{*{20}c}~~~\,x^2&+~~8x&+~~3& \div&\left|\!{\underline{\,{x+2}\,}}\right.&=&x\,+ \,6\,-\,\dfrac9{x+2}.\\
    -~x^2&-~~2x&\\\cline{0-1}
    &~~~\,~6x&+~~3&\\
    &-~\,\,6x&-\,12&\\\cline{2-3}
    &&-~~9
    \end{array}$

    Ufff... it's been a long time I used to type long division
    Your's looks so much nicer than mine... Time I learnt some more LaTeX
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