hi, i need to divide x^3+9x^2+20x+12 by X+6. I can do long div with numbers, but i struggle to do it with equations, could any one please do it step by step and explain the steps pls? thank you

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- Dec 11th 2007, 08:40 AM #1

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- Dec 11th 2007, 10:10 AM #2

- Dec 11th 2007, 10:35 AM #3
This is painful, but let's do it.

$\displaystyle

\noindent\begin{array}{*{20}c}~~~\,x^3&+~~\,9x^2&+ ~~\,20x&+~~\,12&\div&\left|\!{\underline{\,{x\,+\, 6}\,}}\right.&=&x^2\,+\,3x\,+\,2.\\

-~\,x^3&-~~\,6x^2&\\\cline{0-1}

&~~~\,~\,3x^2&+~~\,20x&\\

&-\;\;\;3x^2&-\,~\,\,18x&\\\cline{2-3}

&&~~~~\;\;\,\,2x&+~~\,12&\\

&&-~~\;\;\,2x&-~~\,12&\\\cline{3-4}

\end{array}

$

And we're done