[FONT='Calibri','sans-serif']can anyone help me with the following:[/FONT] [FONT='Calibri','sans-serif']i have an equation - as attachment[/FONT] i need to find the ratio n/m
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Originally Posted by richard_c The equation above an equation for the discharge flowrate K=32x 10-6 q= 5.5l/s d=91.9mm I am trying to find the ratio n/m Do i take my n over d to the m and change it to d ? If so what is the next step? I see litre and mm there.I'm not sure whether it needs, but first you have to equalize the units. Then you can solve the equation for n/m. You can find for your values now.
Hi WIngless, Thanks very much for your help. May I ask a question, as I dont understand maths that easy. in the transition between the two top equations, why is it that the power can just be moved across? Im not doubting you, I just want to learn why. THanks
Hello, Richard! Find the ratio We have: . Take logs: . Therefore: .
Hi, When i punch the figures into the top equation, the figure comes out as -550!??! I cant get the bottom equation to work, at all! Can someone help me out? Thanks
Originally Posted by richard_c Hi, When i punch the figures into the top equation, the figure comes out as -550!??! I cant get the bottom equation to work, at all! Can someone help me out? Thanks What top and what bottom equation? The only one I can think to help you with is Using the numbers in the units you gave: -Dan
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