[FONT='Calibri','sans-serif']can anyone help me with the following:[/FONT]

[FONT='Calibri','sans-serif']i have an equation - as attachment[/FONT]

i need to find the ratio n/m

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- December 10th 2007, 01:07 PMrichard_cLogs Problem
[FONT='Calibri','sans-serif']can anyone help me with the following:[/FONT]

[FONT='Calibri','sans-serif']i have an equation - as attachment[/FONT]

i need to find the ratio n/m - December 10th 2007, 01:28 PMwingless
- December 10th 2007, 03:40 PMrichard_cin response
Hi WIngless,

Thanks very much for your help.

May I ask a question, as I dont understand maths that easy.

http://www.mathhelpforum.com/math-he...54e37260-1.gif

http://www.mathhelpforum.com/math-he...74d6b77d-1.gif

in the transition between the two top equations, why is it that the power can just be moved across? Im not doubting you, I just want to learn why.

THanks - December 10th 2007, 07:59 PMSoroban
Hello, Richard!

Quote:

Find the ratio

We have: .

Take logs: .

Therefore: .

- December 11th 2007, 05:17 AMrichard_cresponse
Hi,

When i punch the figures into the top equation, the figure comes out as -550!??!

I cant get the bottom equation to work, at all! Can someone help me out?

Thanks - December 11th 2007, 07:41 AMtopsquark