# Log squared???

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• Dec 10th 2007, 08:18 AM
dapos
Log squared???
Not sure even is this the right maths section but can anyone explain log squared to me. by log squared i mean log^2(x) not log(x)^2. It came up in an equation in work and we can't figure it out. I'm guessing its a different entity like ln or e.

Can anyone help?
• Dec 10th 2007, 08:22 AM
colby2152
Quote:

Originally Posted by dapos
Not sure even is this the right maths section but can anyone explain log squared to me. by log squared i mean log^2(x) not log(x)^2. It came up in an equation in work and we can't figure it out. I'm guessing its a different entity like ln or e.

Can anyone help?

Do you mean log based two?
• Dec 10th 2007, 08:24 AM
dapos
no i don't mean base 2. Assuming the base is 10 and ^2 means squared. so log^2(x)
• Dec 10th 2007, 08:26 AM
colby2152
Quote:

Originally Posted by dapos
no i don't mean base 2. Assuming the base is 10 and ^2 means squared. so log^2(x)

I would assume this equates to log(x)log(x)
• Dec 10th 2007, 08:27 AM
dapos
no it doesn't equate to log(x)log(x). that is (log(x))^2 sure. i mean Log^2(x)
• Dec 10th 2007, 08:31 AM
colby2152
Quote:

Originally Posted by dapos
no it doesn't equate to log(x)log(x). that is (log(x))^2 sure. i mean Log^2(x)

Then it can only mean log(2x), i.e. 10^log(2x) = 2x
• Dec 10th 2007, 08:32 AM
topsquark
Quote:

Originally Posted by colby2152
Then it can only mean log(2x), i.e. 10^log(2x) = 2x

Or perhaps \$\displaystyle log(log(x))\$?

-Dan
• Dec 10th 2007, 08:39 AM
dapos
find attached a section of the formula with the log^2 as described.
• Dec 10th 2007, 08:41 AM
janvdl
Quote:

Originally Posted by dapos
find attached a section of the formula with the log^2 as described.

I think i had a question like this once too(I might be wrong).

Treat \$\displaystyle log^2 f = x^2\$ and log \$\displaystyle f = x\$ ??
• Dec 10th 2007, 08:49 AM
topsquark
Quote:

Originally Posted by dapos
find attached a section of the formula with the log^2 as described.

Without any other information I would see this as log(x) log(x). What's the rest of the formula and what are you expected to do with it? Perhaps that would help.

-Dan
• Dec 10th 2007, 09:22 AM
colby2152
Quote:

Originally Posted by topsquark
Without any other information I would see this as log(x) log(x). What's the rest of the formula and what are you expected to do with it? Perhaps that would help.

-Dan

This is the same thing I could assume. Like Dan said, we need more information on the nature of the problem. You said it was for work? What are you analyzing and how are you doing this?
• Dec 10th 2007, 12:36 PM
Jhevon
Quote:

Originally Posted by dapos
find attached a section of the formula with the log^2 as described.

I agree with topsquark. from you pic it seems to me that they want you to manipulate the expression like a quadratic equation, in which case we would use \$\displaystyle \log^2 f = (\log f )^2\$
• May 14th 2008, 06:51 AM
SCA
Quote:

Originally Posted by dapos
Not sure even is this the right maths section but can anyone explain log squared to me. by log squared i mean log^2(x) not log(x)^2. It came up in an equation in work and we can't figure it out. I'm guessing its a different entity like ln or e.

Can anyone help?

This weblink may be helpful. You seem to be looking at the same equation I was looking at. In short: log^2(f) = (log(f))^2.

• Jan 28th 2009, 03:03 PM
thebomb551
Log^2(x), I'm pretty sure that this is log(log(x)), If it isn't then i want to know what log iterated is if anyone knows...
For example: log^2(10) = 0 ( log(10) = 1, log(1) = 0)
so log^2(10^10) = 1
• Jan 28th 2009, 05:06 PM
PanZerOlas
couldn't this be like the sin and cos functions?

when we use sin^2(x) we mean sin(x)*sin(x)
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