1. ## an expression problem

this is the problem at hand;

a^2/a-5 + a-30/a-5

Ok, knowing that the denominator (a-5) is the same on both sides it's only a matter of adding the numerators a^2 + a-30 right?!

If so, then will the answe be a^3-30/a-5? or should I factor it out but if so then would it be a^2-6??

Any help would be appretiated!!! thanks

2. Originally Posted by Morzilla
this is the problem at hand;

a^2/a-5 + a-30/a-5

Ok, knowing that the denominator (a-5) is the same on both sides it's only a matter of adding the numerators a^2 + a-30 right?!

If so, then will the answe be a^3-30/a-5? or should I factor it out but if so then would it be a^2-6??

Any help would be appretiated!!! thanks

$\displaystyle \frac{a^2}{(a-5)} + \frac{(a-30)}{(a-5)}$
$\displaystyle \frac{a^2 + a - 30}{a-5}$

This is where you missed out on the factoring... You want two numbers that add up to 1 but the product of these two numbers is -30. The only solution to that is -5 and 6.

$\displaystyle \frac{(a-5)(a+6)}{a-5}$
$\displaystyle a+6$