Results 1 to 3 of 3
Like Tree1Thanks
  • 1 Post By skeeter

Thread: Advanced Functions help please?

  1. #1
    Newbie
    Joined
    May 2015
    From
    Toronto
    Posts
    5

    Advanced Functions help please?

    Profit, P, in dollars from the sale of x MP3 players is given with the following function.

    P(x) = R(x) - C(x)

    Where R(x) = x(350 - 0.000325 x^2)
    and C(x) = 0.00015 x^3 + 100x
    DETERMINE AN EQUATION FOR THE FUNCTION.

    I.E if x = 100 then R = 34675 and C = 10150 so P = 24525

    The back of the book gives me the answer as the equation being
    P(x) = 250x - 0.000475 x^3.
    Yes this works of course it works it gives me the same answer of 24525.
    I just don't understand how the back of the book got that equation.

    Is there anyone who can explain how that equation was created?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    16,216
    Thanks
    3702

    Re: Advanced Functions help please?

    $\displaystyle P(x) = R(x) - C(x)$

    $\displaystyle P(x) = x(350-0.000325x^2) - (0.00015x^3 + 100x)$

    $\displaystyle P(x) = 350x-0.000325x^3 - 0.00015x^3 - 100x$

    $\displaystyle P(x) = 250x - 0.000475x^3$
    Thanks from FeelGood
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    May 2015
    From
    Toronto
    Posts
    5

    Re: Advanced Functions help please?

    Thanks a lot I was having an issue because there was no 0 at the end of 0.00015 I going quick and not reading thoroughly. So I kept doing 0.000015 thinking it was 15 at the end not 150 . Silly mistake I got it now thanks a lot skeeter.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Advanced Functions HELP!!!
    Posted in the New Users Forum
    Replies: 4
    Last Post: Oct 22nd 2013, 06:58 PM
  2. 15x^2 + x - 6 = 0 ... advanced functions....?
    Posted in the Algebra Forum
    Replies: 1
    Last Post: Feb 4th 2013, 07:12 PM
  3. advanced functions questions
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: Mar 25th 2009, 06:32 PM
  4. Advanced functions
    Posted in the Pre-Calculus Forum
    Replies: 7
    Last Post: Oct 15th 2007, 04:21 AM
  5. advanced functions
    Posted in the Calculus Forum
    Replies: 1
    Last Post: Aug 9th 2007, 02:16 PM

Search Tags


/mathhelpforum @mathhelpforum