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Math Help - Help please! Simplify algebraic expressions

  1. #1
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    Help please! Simplify algebraic expressions

    here it is, thanks in adance, need to simplify this

    (3t^-5)^3 divided by 3t^2 and the ^ means to the power of. Thanks
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  2. #2
    Senior Member DivideBy0's Avatar
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    Quote Originally Posted by MathMack View Post
    here it is, thanks in adance, need to simplify this

    (3t^-5)^3 divided by 3t^2 and the ^ means to the power of. Thanks
    Hi Mathmack

    \frac{(3t^{-5})^3}{3t^2}

    =\frac{3^3 \times t^{-5 \times 3}}{3t^2}

    =\frac{27t^{-15}}{3t^2}

    =\frac{27}{3t^2} \times \frac{1}{t^{15}}

    =\frac{9}{t^{17}}
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  3. #3
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    I got everything right but until the multiply step, how or why did you do that. Thanks for your help!
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  4. #4
    Senior Member DivideBy0's Avatar
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    Because t^{-15}=\frac{1}{t^{15}}
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  5. #5
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    i'm sorry i'm just lost, i know you get 27/3t^2 times 1/t^15 not sure how to get the answer you got with that. thanks again
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  6. #6
    Senior Member DivideBy0's Avatar
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    Quote Originally Posted by MathMack View Post
    i'm sorry i'm just lost, i know you get 27/3t^2 times 1/t^15 not sure how to get the answer you got with that. thanks again
    \frac{27}{3t^2} \times \frac{1}{t^{15}}

    =\frac{27}{3t^{2+15}} (multiplying powers of t)

    =\frac{27}{3t^{17}}

    =\frac{9}{t^{17}} (canceling 3's)
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