here it is, thanks in adance, need to simplify this (3t^-5)^3 divided by 3t^2 and the ^ means to the power of. Thanks
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Originally Posted by MathMack here it is, thanks in adance, need to simplify this (3t^-5)^3 divided by 3t^2 and the ^ means to the power of. Thanks Hi Mathmack $\displaystyle \frac{(3t^{-5})^3}{3t^2}$ $\displaystyle =\frac{3^3 \times t^{-5 \times 3}}{3t^2}$ $\displaystyle =\frac{27t^{-15}}{3t^2}$ $\displaystyle =\frac{27}{3t^2} \times \frac{1}{t^{15}}$ $\displaystyle =\frac{9}{t^{17}}$
I got everything right but until the multiply step, how or why did you do that. Thanks for your help!
Because $\displaystyle t^{-15}=\frac{1}{t^{15}}$
i'm sorry i'm just lost, i know you get 27/3t^2 times 1/t^15 not sure how to get the answer you got with that. thanks again
Originally Posted by MathMack i'm sorry i'm just lost, i know you get 27/3t^2 times 1/t^15 not sure how to get the answer you got with that. thanks again $\displaystyle \frac{27}{3t^2} \times \frac{1}{t^{15}}$ $\displaystyle =\frac{27}{3t^{2+15}}$ (multiplying powers of t) $\displaystyle =\frac{27}{3t^{17}}$ $\displaystyle =\frac{9}{t^{17}}$ (canceling 3's)
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