4^1996 - 4^1995 - 4^1994 + 4^1993 = 45(2^X) Solve for X
Follow Math Help Forum on Facebook and Google+
4^1996 - 4^1995 - 4^1994 + 4^1993 = 45(2^x) 4^1993(4^3 - 4^2 - 4^1 + 4^0) = 45(2^x) 2^3986*45 = 45*(2^x) x = 3986
Originally Posted by stones44 4^1996 - 4^1995 - 4^1994 + 4^1993 = 45(2^X) Solve for X Set Then we have:
Originally Posted by stones44 4^1996 - 4^1995 - 4^1994 + 4^1993 = 45(2^X) Solve for X Thus, . Now convert both sides to base 2 and finish the problem.
Hehehe, 3 answers to one problem. At least all of them are right.
Originally Posted by janvdl Hehehe, 3 answers to one problem. At least all of them are right. That was great guys -- working together in harmony!
Originally Posted by colby2152 That was great guys -- working together in harmony! I would say it was simply all of us posting at the same time...
View Tag Cloud