Solve 7 = 4
3x x-2 do i need to multiply and leave it like this 7x-14=12x ?
Hello,
I assume that you mean:
$\displaystyle \frac{7}{3x} =\frac{4}{x-2} \ .\ x \neq 0~\wedge~x \neq 2$
Multiply bot sides by the denominators and cancel:
$\displaystyle
\frac{7\cdot 3x \cdot (x-2)}{3x} =\frac{4 \cdot 3x \cdot (x-2)}{x-2}~\implies~7x-14=12x~\implies~-14=5x$ $\displaystyle ~\implies~ x=-\frac{14}5$