x(.60)=y
y(3.1699)=z
z+y=892,189
what is X
Hello,Originally Posted by kurtolios
you have a system of three linear equations:
$\displaystyle \left \{\begin{array}{ccc}.6 \cdot x+y=0\\3.1699 \cdot y+z=0\\y+z=892.189\end{array}\right.$
You'll get the approximate solutions:
x = -356.59887927...
y = 213.959327562...
z = 678.229672438...
Greetings
EB