How would one go about factoring the binomial a^6 - b^3 The only thing I can come up with is a^3 (a-b)(a^2+ab+b^2) , but this can't be right because you would have to distribute the a^3. Any ideas?
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Difference of two cubes: $\displaystyle (a^{2})^{3}-(b)^{3}$ $\displaystyle (a^{2}-b)(a^{4}+a^{2}b+b^{2})$
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