3x^2-5x-2
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6x^3+2x^2+3x+1'
k. I simplified it down to this but i couldn't go any further.
(3x-1)(x+2)
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(6x^3+2x^2)+(3x+1)
Thanks for the help in advance.
The numerator becomes,Originally Posted by ayanami_00
$\displaystyle (3x+1)(x-2)$
The denominator can be re-grouped as,
$\displaystyle 3x(2x^2+1)+(2x^2+1)$ thus,
$\displaystyle (3x+1)(2x^2+1)$
Thus, you have,
$\displaystyle \frac{(3x+1)(x-2)}{(3x+1)(2x^2+1)}$
Thus,
$\displaystyle \frac{x-2}{2x^2+1}$