Can someone please help me simplfiy this? $\displaystyle \frac{-2+\sqrt{12}}{-2} $ Thank you!
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Originally Posted by Coach Can someone please help me simplfiy this? $\displaystyle \frac{-2+\sqrt{12}}{-2} $ Thank you! Let's start with the $\displaystyle \sqrt{12}$: $\displaystyle \sqrt{12} = \sqrt{4 \cdot 3} = \sqrt{4} \cdot \sqrt{3}$ $\displaystyle = \sqrt{2^2} \cdot \sqrt{3} = 2 \sqrt{3}$ Put that into your fraction and simplify. -Dan
$\displaystyle \frac{-2+2\sqrt{3}}{-2}$ Is it like this? Am I allowed to simplify it further by dividing 2 by -2 ?
Originally Posted by Coach $\displaystyle \frac{-2+2\sqrt{3}}{-2}$ Is it like this? Am I allowed to simplify it further by dividing 2 by -2 ? Hello, be careful! You only can cancel factors never summands: $\displaystyle \frac{-2+2\sqrt{3}}{-2}=\frac{-2(1-\sqrt{3})}{-2}$ and now it is possible to cancel.
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