# Thread: Need help with word problem...

1. ## Need help with word problem...

The length of a rectangle is 3cm greater tan the width. If each dimension is increased by 2cm, the area is increased by 26cm². Find the original dimension of the rectangle.

Ok.. i wrote this to try to solve it but somewhere along the line im wrong and keep getting the wrong answer..can someone please show me what im doing wrong

(w + 2) (l + 2) = a + 26
(w + 2 + 3) (w + 2) = (w + 3) (w + 26)

2. Hello, (-__-)!

The length of a rectangle is 3 cm greater than the width.
If each dimension is increased by 2 cm, the area is increased by 26 cm².
Find the original dimension of the rectangle.

Let $W$ = width of the rectangle.
Then $W + 3$ = length of the rectangle.

The area of this rectangle is: . $W(W+3)$ m².

If each dimension is increased by 2 cm,
. . the new width is: $W + 2$,
. . the new length is: $W + 5$

The area of the new triangle is: . $(W+2)(W+5)$ m².

We're told that the new area is 26 m² more than the original area.

There is our equation! . . . . . $(W+2)(W+5) \;=\;W(W+3) + 26$

Can you finish it now?