The length of a rectangle is 3cm greater tan the width. If each dimension is increased by 2cm, the area is increased by 26cm². Find the original dimension of the rectangle.
Ok.. i wrote this to try to solve it but somewhere along the line im wrong and keep getting the wrong answer..can someone please show me what im doing wrong
(w + 2) (l + 2) = a + 26
(w + 2 + 3) (w + 2) = (w + 3) (w + 26)
Hello, (-__-)!
The length of a rectangle is 3 cm greater than the width.
If each dimension is increased by 2 cm, the area is increased by 26 cm².
Find the original dimension of the rectangle.
Let= width of the rectangle.
Then= length of the rectangle.
The area of this rectangle is: .m².
If each dimension is increased by 2 cm,
. . the new width is:,
. . the new length is:
The area of the new triangle is: .m².
We're told that the new area is 26 m² more than the original area.
There is our equation! . . . . .
Can you finish it now?
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