# Thread: Check work...Algebra 2 packet

1. ## Check work...Algebra 2 packet

I was wondering if maybe someone might be able to take a look at this? I have been having a very hard time with it.

2. #6. How many integer solutions does this inequality have? $|x+12| \leq 3$

The answer is not zero. Try plugging in x = -9, -10, -11, -12, -13, -14, or -15. Seven different possible solutions. To solve for this algebraically, think of the absolute value as a boundary...

$- 3 \leq x+12 \leq 3$

3. Thank you very much! I appreciate you taking the time to look over my work...are there any problems with any of the others?

4. #8 on page 1 is wrong: D would give an inequality of $x\geq-5$. The graph does not represent this.

Page 4:

#2. You found the y-int. To find the x-int you must plug 0 into y to find where it will hit the x-axis.

#3. Slope is $\frac{rise}{run}$. You did it backwards. It should be up 2 over 3. $\frac{2}{3}=C$

5. I am a little confused on number 4 on page 1...can anyone help me with that...now that i look at it, it looks like student B might be correct?

6. No your answer is correct Neither student performed the distribution correct, Student b however somehow got the answer correct. Perhaps this is a trick perhaps a mistake in the question. Neither student, however distributed correctly.

Student B made a mistake in distributing. In front of the parenthesis is -2. So you multiply that -2 by everything inside the parenthesis. It should be:
$4x+(-2)(-x)+(-2)(3)=4x+(2x)+(-6)=4x+2x-6=6x-6$