I was wondering if maybe someone might be able to take a look at this? I have been having a very hard time with it.
#6. How many integer solutions does this inequality have? $\displaystyle |x+12| \leq 3$
The answer is not zero. Try plugging in x = -9, -10, -11, -12, -13, -14, or -15. Seven different possible solutions. To solve for this algebraically, think of the absolute value as a boundary...
$\displaystyle - 3 \leq x+12 \leq 3$
#8 on page 1 is wrong: D would give an inequality of $\displaystyle x\geq-5$. The graph does not represent this.
Page 4:
#2. You found the y-int. To find the x-int you must plug 0 into y to find where it will hit the x-axis.
#3. Slope is $\displaystyle \frac{rise}{run}$. You did it backwards. It should be up 2 over 3. $\displaystyle \frac{2}{3}=C$
No your answer is correct Neither student performed the distribution correct, Student b however somehow got the answer correct. Perhaps this is a trick perhaps a mistake in the question. Neither student, however distributed correctly.
Student B made a mistake in distributing. In front of the parenthesis is -2. So you multiply that -2 by everything inside the parenthesis. It should be:
$\displaystyle 4x+(-2)(-x)+(-2)(3)=4x+(2x)+(-6)=4x+2x-6=6x-6$