# Thread: linear quadratic equation

1. ## linear quadratic equation

solve equation algebraically, check all solutions

y=x squared - x
x+y=4

2. Originally Posted by blame_canada100
solve equation algebraically, check all solutions

y=x squared - x
x+y=4
you mean, solve the system of equations...

from the second equation, we see that $y = 4 - x$, plug this into the first equation, we get

$4 - x = x^2 - x$

now continue. solve for all the values of $x$ and then plug them into $y = 4 - x$ to find the corresponding values for $y$

3. I got x + (x^2 - x) = 4
x^2 = 4
x = 2 or -2
2 + y = 4
y = 2
-2 + y = 4
y = 6

When x is 2 y is 2, when x is -2 y is 6
(2,2) (-2,6) or the possible solutions