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Math Help - linear quadratic equation

  1. #1
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    linear quadratic equation

    solve equation algebraically, check all solutions

    y=x squared - x
    x+y=4
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by blame_canada100 View Post
    solve equation algebraically, check all solutions

    y=x squared - x
    x+y=4
    you mean, solve the system of equations...

    from the second equation, we see that y = 4 - x, plug this into the first equation, we get

    4 - x = x^2 - x

    now continue. solve for all the values of x and then plug them into y = 4 - x to find the corresponding values for y
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  3. #3
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    I got x + (x^2 - x) = 4
    x^2 = 4
    x = 2 or -2
    2 + y = 4
    y = 2
    -2 + y = 4
    y = 6

    When x is 2 y is 2, when x is -2 y is 6
    (2,2) (-2,6) or the possible solutions
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