1. ## Math Help, Algebra

My Math teacher gave us 50 problems for over the weekend.

Write an equation of the line that is parallel to the given line and passes through the given point.

1. y=2x+2 (y=3, x=2)

2. y=-2x+3 (y=4, x=4)

3. y=2/3x-2 (y=2, x=1)

4. y=-4x-2 (y=5, x=3)

5. y=-9x-8 (y=7, x=-2)

PS I might post a word problem or two if I have a problem.

Edit: Sorry I'm really "math dumb" and so... yea I'm using Yahoo answers. Thx for the replies.

2. Originally Posted by doomdesire34
My Math teacher gave us 50 problems for over the weekend.

Write an equation of the line that is parallel to the given line and passes through the given point.

1. y=2x+2 (y=3, x=2)

2. y=-2+3 (y=4, x=4)

3. y=2/3x-2 (y=2, x=1)

4. y=-4x-2 (y=5, x=3)

5. y=-9x-8 (y=7, x=-2)

PS I might post a word problem or two if I have a problem.
okay, i'll do 1, and do the rest..

given the equation of the line, it can be determined that the slope of the line is 2.. since a point is given where the line parallel to the given line should pass, then use the slope-point form..

so, (y-3) = 2 (x-2) or y = 2x - 4 + 3 = 2x-1..

got it?

another thing, group the terms accordingly so that there will be no confusions..

3. Originally Posted by doomdesire34
My Math teacher gave us 50 problems for over the weekend.

Write an equation of the line that is parallel to the given line and passes through the given point.

1. y=2x+2 (y=3, x=2)

2. y=-2+3 (y=4, x=4)

3. y=2/3x-2 (y=2, x=1)

4. y=-4x-2 (y=5, x=3)

5. y=-9x-8 (y=7, x=-2)

PS I might post a word problem or two if I have a problem.
note that the new line has the same slope as the line we are considering. once you have that, use the point-slope form to get the equation.

recall that the point-slope form says the equation of the line with slope $m$ passing through the point $(x_1,y_1)$ is given by:

$y - y_1 = m(x - x_1)$

so, for the first:

we want the line parallel to $y = 2x + 2$ that passes through $(2,3)$

we have $m = 2$ here, thus the line we want is:

$y - 3 = 2(x - 2)$

$\Rightarrow \boxed{y = 2x - 1}$

EDIT: beaten again...