1/R=1/R1+1/R2 The total is 1.2, R1 is x. I got down to 1/R= R1+R2/R1*R2. But from there I'm lost any pointers? Thanks Oh and the answer is 1.2x/x-1.2 I don't know how to get there though.
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$\displaystyle \frac{1}{1.2} = \frac{1}{x} + \frac{1}{R_2} $ $\displaystyle \frac{1}{R_2} = \frac{1}{1.2} - \frac{1}{x} $ $\displaystyle \frac{1}{R_2} = \frac{x - 1.2}{1.2x} $ $\displaystyle R_2 = \frac{1.2x}{x-1.2} $
Originally Posted by tukeywilliams $\displaystyle \frac{1}{1.2} = \frac{1}{x} + \frac{1}{R_2} $ $\displaystyle \frac{1}{R_2} = \frac{1}{1.2} - \frac{1}{x} $ $\displaystyle \frac{1}{R_2} = \frac{x - 1.2}{1.2x} $ $\displaystyle R_2 = \frac{1.2x}{x-1.2} $ how did you get from this part $\displaystyle \frac{1}{R_2} = \frac{x - 1.2}{1.2x} $ to this part $\displaystyle R_2 = \frac{1.2x}{x-1.2} $ thank you so much for the help
I took the reciprocal.
Originally Posted by tukeywilliams I took the reciprocal. of course.. man I'm stupid
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