Results 1 to 5 of 5

Thread: imaginary solutions

  1. November 28th 2007, 10:02 AM #1
    Gaskina
    Gaskina is offline
    Newbie
    Joined
    Nov 2007
    Posts
    4

    imaginary solutions

    3v^2 + 4v-1=0
    Follow Math Help Forum on Facebook and Google+
  2. November 28th 2007, 11:03 AM #2
    Gaskina
    Gaskina is offline
    Newbie
    Joined
    Nov 2007
    Posts
    4

    Angry Does this problem have a solution?

    I believe that you are suppose to square the sides after adding the 1 to both sides, then solve...but it doesn't work out.
    Follow Math Help Forum on Facebook and Google+
  3. November 28th 2007, 11:26 AM #3
    ThePerfectHacker
    ThePerfectHacker is offline
    Global Moderator ThePerfectHacker's Avatar
    Joined
    Nov 2005
    From
    New York City
    Posts
    10,603
    Quote Originally Posted by Gaskina View Post
    3v^2 + 4v-1=0
    Are you allowed to use the quadradic formula?
    Follow Math Help Forum on Facebook and Google+
  4. November 28th 2007, 11:40 AM #4
    Gaskina
    Gaskina is offline
    Newbie
    Joined
    Nov 2007
    Posts
    4
    The answer needs to be given in real/imaginary numbers (a set). You can use what ever we've learned in class. The quadratic formula is good.
    Follow Math Help Forum on Facebook and Google+
  5. November 28th 2007, 11:46 AM #5
    ThePerfectHacker
    ThePerfectHacker is offline
    Global Moderator ThePerfectHacker's Avatar
    Joined
    Nov 2005
    From
    New York City
    Posts
    10,603
    Quote Originally Posted by Gaskina View Post
    3v^2 + 4v-1=0
    v = \frac{-4\pm \sqrt{4^2 - 4(3)(-1)}}{2(3)}

    v=\frac{-4\pm \sqrt{16 + 12}}{6}

    This means,
    \frac{-4+\sqrt{28}}{6},\frac{-4-\sqrt{28}}{6}
    Follow Math Help Forum on Facebook and Google+
« Logarithms | Math - Algebra Word Problem »

Similar Math Help Forum Discussions

  1. Infinitely many solutions (Edit: No solutions)
    Posted in the Algebra Forum
    Replies: 1
    Last Post: October 4th 2011, 08:21 PM
  2. How do I find the imaginary number solutions to this problem?
    Posted in the Algebra Forum
    Replies: 4
    Last Post: January 18th 2011, 03:34 PM
  3. For which values of k are there no solutions, 1 solution, inifinite solutions.
    Posted in the Advanced Algebra Forum
    Replies: 6
    Last Post: July 26th 2010, 11:45 AM
  4. real and imaginary solutions
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: March 20th 2010, 08:21 PM
  5. Solutions for imaginary numbers in a+bi
    Posted in the Pre-Calculus Forum
    Replies: 5
    Last Post: January 31st 2010, 03:24 PM

Search Tags


/mathhelpforum @mathhelpforum