# Math Help - imaginary solutions

1. ## imaginary solutions

3v^2 + 4v-1=0

2. ## Does this problem have a solution?

I believe that you are suppose to square the sides after adding the 1 to both sides, then solve...but it doesn't work out.

3. Originally Posted by Gaskina
3v^2 + 4v-1=0
Are you allowed to use the quadradic formula?

4. The answer needs to be given in real/imaginary numbers (a set). You can use what ever we've learned in class. The quadratic formula is good.

5. Originally Posted by Gaskina
3v^2 + 4v-1=0
$v = \frac{-4\pm \sqrt{4^2 - 4(3)(-1)}}{2(3)}$

$v=\frac{-4\pm \sqrt{16 + 12}}{6}$

This means,
$\frac{-4+\sqrt{28}}{6},\frac{-4-\sqrt{28}}{6}$