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Math Help - imaginary solutions

  1. #1
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    imaginary solutions

    3v^2 + 4v-1=0
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  2. #2
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    Angry Does this problem have a solution?

    I believe that you are suppose to square the sides after adding the 1 to both sides, then solve...but it doesn't work out.
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  3. #3
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    Quote Originally Posted by Gaskina View Post
    3v^2 + 4v-1=0
    Are you allowed to use the quadradic formula?
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  4. #4
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    The answer needs to be given in real/imaginary numbers (a set). You can use what ever we've learned in class. The quadratic formula is good.
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  5. #5
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    Quote Originally Posted by Gaskina View Post
    3v^2 + 4v-1=0
    v = \frac{-4\pm \sqrt{4^2 - 4(3)(-1)}}{2(3)}

    v=\frac{-4\pm \sqrt{16 + 12}}{6}

    This means,
    \frac{-4+\sqrt{28}}{6},\frac{-4-\sqrt{28}}{6}
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