3v^2 + 4v-1=0
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I believe that you are suppose to square the sides after adding the 1 to both sides, then solve...but it doesn't work out.
Originally Posted by Gaskina 3v^2 + 4v-1=0 Are you allowed to use the quadradic formula?
The answer needs to be given in real/imaginary numbers (a set). You can use what ever we've learned in class. The quadratic formula is good.
Originally Posted by Gaskina 3v^2 + 4v-1=0 $\displaystyle v = \frac{-4\pm \sqrt{4^2 - 4(3)(-1)}}{2(3)}$ $\displaystyle v=\frac{-4\pm \sqrt{16 + 12}}{6}$ This means, $\displaystyle \frac{-4+\sqrt{28}}{6},\frac{-4-\sqrt{28}}{6}$
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