I need to solve the equation. $\displaystyle log_x\frac{1}{8}=3 $ I come up with $\displaystyle \frac{1}{8}=x^3 $ I'm guessing you can reduce this even further, but I'm not sure how. Thanks Jason
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Originally Posted by Darkhrse99 I need to solve the equation. $\displaystyle log_x\frac{1}{8}=3 $ I come up with $\displaystyle \frac{1}{8}=x^3 $ Hello, $\displaystyle \frac{1}{8}=x^3 ~\iff~ \left(\frac12\right)^3 =x^3~\iff~x=\frac12$ or: $\displaystyle \frac{1}{8}=x^3~\iff~x=\sqrt[3]{\frac18} = \frac12$
Thanks, It' been a long night and I think my brain is shutting down.
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