$\displaystyle log_{2}(1/x)+ log_{2}(1/x^2) $
I know that addition is equal to multiplication
I think it starts out as $\displaystyle log{2} (1/x)(1/x^2)$
But I'm not sure where to go from there.
$\displaystyle log_{2}(1/x)+ log_{2}(1/x^2) $
I know that addition is equal to multiplication
I think it starts out as $\displaystyle log{2} (1/x)(1/x^2)$
But I'm not sure where to go from there.