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Math Help - How would you write this eq. as a single logerith?

  1. #1
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    How would you write this eq. as a single logerith?

     log_{2}(1/x)+ log_{2}(1/x^2)

    I know that addition is equal to multiplication

    I think it starts out as  log{2} (1/x)(1/x^2)
    But I'm not sure where to go from there.
    Last edited by Darkhrse99; November 27th 2007 at 08:03 PM.
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  2. #2
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    Quote Originally Posted by Darkhrse99 View Post
     log_{2}(1/x)+ log_{2}(1/x^2)

    I know that addiotion is equal to multiplication

    I think it starts out as [tex] log{2} {1/x}{1/x^2}
    But I'm not sure where to go from there.
    \log_2 \frac{1}{x} + \log_2 \frac{1}{x^2} =\log_2 \frac{1}{x^3} = \log_2 x^{-3} = - 3 \log_2 x
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