# How would you write this eq. as a single logerith?

• November 27th 2007, 07:50 PM
Darkhrse99
How would you write this eq. as a single logerith?
$log_{2}(1/x)+ log_{2}(1/x^2)$

I know that addition is equal to multiplication

I think it starts out as $log{2} (1/x)(1/x^2)$
But I'm not sure where to go from there.
• November 27th 2007, 07:55 PM
ThePerfectHacker
Quote:

Originally Posted by Darkhrse99
$log_{2}(1/x)+ log_{2}(1/x^2)$

I know that addiotion is equal to multiplication

I think it starts out as [tex] log{2} {1/x}{1/x^2}
But I'm not sure where to go from there.

$\log_2 \frac{1}{x} + \log_2 \frac{1}{x^2} =\log_2 \frac{1}{x^3} = \log_2 x^{-3} = - 3 \log_2 x$