$\displaystyle log_{2}(1/x)+ log_{2}(1/x^2) $

I know that addition is equal to multiplication

I think it starts out as $\displaystyle log{2} (1/x)(1/x^2)$

But I'm not sure where to go from there.

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- Nov 27th 2007, 06:50 PMDarkhrse99How would you write this eq. as a single logerith?
$\displaystyle log_{2}(1/x)+ log_{2}(1/x^2) $

I know that addition is equal to multiplication

I think it starts out as $\displaystyle log{2} (1/x)(1/x^2)$

But I'm not sure where to go from there. - Nov 27th 2007, 06:55 PMThePerfectHacker