I am stuck on these three problems. I have to find out what x is. Any help would be greatly appreciated.
$\displaystyle 1.06^x=4.1$
$\displaystyle 50e^{.035x}=200$
$\displaystyle 3+2e^{-x}=6$
Thank you!
No it should turn out to be
$\displaystyle ln1.06^x = ln4.1$
$\displaystyle (x)ln1.06 = ln4.1$ because of the power rule
$\displaystyle x = \frac {ln4.1}{ln1.06}$
and just use a calculator to solve that. Well it did come out to be the same answer. Idk because I'm not a helper, so you should ask someone else.