It need to know, including the working out of: √x²-x >-2 Grazie
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Originally Posted by chiara_c It need to know, including the working out of: √x²-x >-2 Grazie Do you mean: $\displaystyle \sqrt{x^2 - x} > -2$ ? Square both sides $\displaystyle x^2 - x > 4$ $\displaystyle x^2 - x - 4 > 0$ I'm sure you can solve it from here -- EDIT: And to think i said just the other day that one never sees Italians on MHF
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