Determine the probablilty that x=5 people will enter in the next minute.

The formula given is p(x) 4^x e^-4/ x!

where x!= x* (x-1)*(x-2).......3*2*1

Thanks

Jason

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- Nov 25th 2007, 08:37 PMDarkhrse99Can some help me on this Log. word problem?
Determine the probablilty that x=5 people will enter in the next minute.

The formula given is p(x) 4^x e^-4/ x!

where x!= x* (x-1)*(x-2).......3*2*1

Thanks

Jason - Nov 25th 2007, 10:17 PMCaptainBlack
- Nov 26th 2007, 01:37 PMDarkhrse99
If I put X=5 i for x I'd get

$\displaystyle

p(x)=\frac{4^5 e^{-4}}{ x!}

$

How would I solve it? - Nov 26th 2007, 06:03 PMJhevon
- Nov 26th 2007, 08:34 PMCaptainBlack
- Nov 27th 2007, 07:40 AMDarkhrse99
$\displaystyle p(x)=\frac{1024 }{120} $ = .15

- Nov 27th 2007, 07:47 AMjanvdl
- Nov 27th 2007, 07:54 AMjanvdl
- Nov 27th 2007, 07:55 AMDarkhrse99
$\displaystyle p(x)=\frac{1024 e^{-4}}{ 120}

$ =.1540 - Nov 27th 2007, 07:58 AMDarkhrse99
$\displaystyle p(x)=\frac{18.4839}{ 120}

$=.1540 chance of someone waling through the door. - Nov 27th 2007, 08:02 AMjanvdl
- Nov 27th 2007, 08:09 AMDarkhrse99
Thanks for the help. I would have never guessed that x! means 5*4*3*2.....

- Nov 27th 2007, 08:12 AMjanvdl
- Nov 27th 2007, 10:34 AMDarkhrse99
I understand it now, but I was never aware of it before. I was never taught that in class, but I have it for homework. It's a little frustrating.

- Nov 27th 2007, 11:40 AMbjhopperprobability
the formula for p(x) you posted must be related to some defined conditions. a p of .15 is high. it could be true in a school office given school population and average daily traffic but the p of this event for visitors coming to my house in the next minute is close to zero. what were your conditions?