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Math Help - Factoring Problem - ex 2

  1. #1
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    Factoring Problem - ex 2

    6x^{3} - 9x^{2} - 216x + 3

    3(2x^{3} - 3x^{2} - 72 + 1)

    3(2x^{3} - 3x^{2} - 71) ??? Correct? Next move?
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  2. #2
    Super Member sakonpure6's Avatar
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    Re: Factoring Problem - ex 2

    $ 6x^3 - 9x^2 -216x +3$
    $ 3(2x^3 - 3x^2-72x+1) $

    So we actually have: $ 3(2x^3 - 3x^2 - 72x +1 )$

    We can use the factor theorem here which states that if f(a)= 0 , (x - a) is a factor; In this case 'a' are all the possible factors of 1 and 1/2. However, f(1)!=0 and f(1/2)!=0 For more information and why a is 1 in this case consult the following link: The Factor Theorem
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