Originally Posted by

**rachael** 20 The number of parts per million, x, of E. coli in a stream t hours after a pollutant

containing E. coli is introduced is modelled by x(t) = loge (t + e^2), t ≥ 0.

a How many parts per million of E. coli are introduced into the stream?

b To the nearest tenth of a part per million, how many parts per million of E. coli are in the stream when t = 10?

could some one help me with part b?

i tried subin t=10

therefore i got x(10)= loge ( 10 + e^2)

= loge 10 * loge e^2

= 4.605

but the answer is wrong.