Originally Posted by rachael
20 The number of parts per million, x, of E. coli in a stream t hours after a pollutant
containing E. coli is introduced is modelled by x(t) = loge (t + e^2), t ≥ 0.
a How many parts per million of E. coli are introduced into the stream?
b To the nearest tenth of a part per million, how many parts per million of E. coli are in the stream when t = 10?
could some one help me with part b?
i tried subin t=10
therefore i got x(10)= loge ( 10 + e^2)
= loge 10 * loge e^2
= 4.605
but the answer is wrong.